Integrand size = 27, antiderivative size = 59 \[ \int \frac {\cos ^2(c+d x) \cot (c+d x)}{a+b \sin (c+d x)} \, dx=\frac {\log (\sin (c+d x))}{a d}+\frac {\left (a^2-b^2\right ) \log (a+b \sin (c+d x))}{a b^2 d}-\frac {\sin (c+d x)}{b d} \]
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Time = 0.08 (sec) , antiderivative size = 59, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {2916, 12, 908} \[ \int \frac {\cos ^2(c+d x) \cot (c+d x)}{a+b \sin (c+d x)} \, dx=\frac {\left (a^2-b^2\right ) \log (a+b \sin (c+d x))}{a b^2 d}+\frac {\log (\sin (c+d x))}{a d}-\frac {\sin (c+d x)}{b d} \]
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Rule 12
Rule 908
Rule 2916
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {b \left (b^2-x^2\right )}{x (a+x)} \, dx,x,b \sin (c+d x)\right )}{b^3 d} \\ & = \frac {\text {Subst}\left (\int \frac {b^2-x^2}{x (a+x)} \, dx,x,b \sin (c+d x)\right )}{b^2 d} \\ & = \frac {\text {Subst}\left (\int \left (-1+\frac {b^2}{a x}+\frac {a^2-b^2}{a (a+x)}\right ) \, dx,x,b \sin (c+d x)\right )}{b^2 d} \\ & = \frac {\log (\sin (c+d x))}{a d}+\frac {\left (a^2-b^2\right ) \log (a+b \sin (c+d x))}{a b^2 d}-\frac {\sin (c+d x)}{b d} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.90 \[ \int \frac {\cos ^2(c+d x) \cot (c+d x)}{a+b \sin (c+d x)} \, dx=\frac {b^2 \log (\sin (c+d x))+\left (a^2-b^2\right ) \log (a+b \sin (c+d x))-a b \sin (c+d x)}{a b^2 d} \]
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Time = 0.36 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.93
method | result | size |
derivativedivides | \(\frac {-\frac {\sin \left (d x +c \right )}{b}+\frac {\ln \left (\sin \left (d x +c \right )\right )}{a}+\frac {\left (a^{2}-b^{2}\right ) \ln \left (a +b \sin \left (d x +c \right )\right )}{a \,b^{2}}}{d}\) | \(55\) |
default | \(\frac {-\frac {\sin \left (d x +c \right )}{b}+\frac {\ln \left (\sin \left (d x +c \right )\right )}{a}+\frac {\left (a^{2}-b^{2}\right ) \ln \left (a +b \sin \left (d x +c \right )\right )}{a \,b^{2}}}{d}\) | \(55\) |
parallelrisch | \(\frac {\left (a^{2}-b^{2}\right ) \ln \left (2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )\right )-a^{2} \ln \left (\sec ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-a b \sin \left (d x +c \right )+\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}}{d a \,b^{2}}\) | \(90\) |
norman | \(\frac {-\frac {2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{b d}-\frac {2 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{b d}}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2}}+\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a d}+\frac {\left (a^{2}-b^{2}\right ) \ln \left (\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \right )}{a \,b^{2} d}-\frac {a \ln \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{b^{2} d}\) | \(142\) |
risch | \(-\frac {i a x}{b^{2}}+\frac {i {\mathrm e}^{i \left (d x +c \right )}}{2 b d}-\frac {i {\mathrm e}^{-i \left (d x +c \right )}}{2 b d}-\frac {2 i a c}{b^{2} d}+\frac {a \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1+\frac {2 i a \,{\mathrm e}^{i \left (d x +c \right )}}{b}\right )}{b^{2} d}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1+\frac {2 i a \,{\mathrm e}^{i \left (d x +c \right )}}{b}\right )}{a d}+\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d a}\) | \(148\) |
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Time = 0.39 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.93 \[ \int \frac {\cos ^2(c+d x) \cot (c+d x)}{a+b \sin (c+d x)} \, dx=\frac {b^{2} \log \left (-\frac {1}{2} \, \sin \left (d x + c\right )\right ) - a b \sin \left (d x + c\right ) + {\left (a^{2} - b^{2}\right )} \log \left (b \sin \left (d x + c\right ) + a\right )}{a b^{2} d} \]
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Timed out. \[ \int \frac {\cos ^2(c+d x) \cot (c+d x)}{a+b \sin (c+d x)} \, dx=\text {Timed out} \]
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Time = 0.21 (sec) , antiderivative size = 54, normalized size of antiderivative = 0.92 \[ \int \frac {\cos ^2(c+d x) \cot (c+d x)}{a+b \sin (c+d x)} \, dx=\frac {\frac {\log \left (\sin \left (d x + c\right )\right )}{a} - \frac {\sin \left (d x + c\right )}{b} + \frac {{\left (a^{2} - b^{2}\right )} \log \left (b \sin \left (d x + c\right ) + a\right )}{a b^{2}}}{d} \]
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Time = 0.32 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.95 \[ \int \frac {\cos ^2(c+d x) \cot (c+d x)}{a+b \sin (c+d x)} \, dx=\frac {\frac {\log \left ({\left | \sin \left (d x + c\right ) \right |}\right )}{a} - \frac {\sin \left (d x + c\right )}{b} + \frac {{\left (a^{2} - b^{2}\right )} \log \left ({\left | b \sin \left (d x + c\right ) + a \right |}\right )}{a b^{2}}}{d} \]
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Time = 11.72 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.66 \[ \int \frac {\cos ^2(c+d x) \cot (c+d x)}{a+b \sin (c+d x)} \, dx=\frac {\ln \left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{a\,d}-\frac {\sin \left (c+d\,x\right )}{b\,d}+\frac {\ln \left (a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+2\,b\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )+a\right )\,\left (\frac {a}{b^2}-\frac {1}{a}\right )}{d}-\frac {a\,\ln \left ({\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+1\right )}{b^2\,d} \]
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